Find inflection point for the function f(x) = x^3 - 6x^2 + 15.
Group of answer choices
X = 0
x = 4
x = 2
x = -12
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3. Consider the function f(x) = x2 - 6x^2 - 5 a. Find the values of x such that f'(x) = 0. b. Use the results of part a to: find interval(s) on which the function is increasing and interval(s) on which it is decreasing. c. Find the value(s) of x such that f"(x)=0. d. Use the result of part c to find interval(s) on which f(x) is concave up and interval(s) on which it is concave down. e. Sketch...
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please do both Find the relative extrema and the points of inflection f any exist)of the function. Use a graphing utility to graph the function and confirm your results. (Round your answers to three decimal places. If an answer does not exist, enter DNE maximum inflection point x, y) smaller a-value) rflection poin x, y) larger x-value) Need Help? at oter 15. 0.5/1 points | Previous Answers LarCalc11 5.4.089 For large values of n, n! = 1.2.3.4 (n-1):n can be...
Find the inflection points. Find the interval on which f is concave up. Find the interval on which f is concave down. Step 1 We have f'(x) = 4 cos(x) – 4 sin(x), so f"(x) = -4 cos (x) – 4 sin (x) - 4 sin(x) – 4 cos(x) which equals 0 when tan(x) = -1 Hence, in the Interval o <x< 211, f'(x) = 0 77 when X = 371 4 7 л 4 and x = Step 2...
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