Newton's Laws, Work & Kinetic Energy
You weigh
How much work is done by the spring as the two of you are brought to rest by friction?
Express the answer to three significant figures and include the appropriate units.
Homework Answers
SOLUTION :
Spring constant
= my weight / compression
= 530 / 1.80 kg/cm
= 294.44 kg/cm
By putting additional weight pf dog of 180 N, additional compression of spring
= 180/294.44
= 0.61132 cm
= 0.061132 m
So,
Work done
= Total weight of mine and dog moves by additional compression
= (530 + 180) * 0.061132 N-m
= 43.404 N-m
= 43.404 J (ANSWER).
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Please help with any or all problems I can’t seem to
figure them out thanks
An automobile having a mass of 1,000 kg is driven into a brick wll in a safety test. The bumper behaves like a spring with constant 4.35 x 10 N/m and is compressed 2.45 cm as the car is brought to rest. What was the speed of the car before impact, assuming no energy is lost in the collision with the wall? m/s Need Help?...
Please show work and use the numbers provided so that I can
compare it to my own work and figure out how to do it on my own.
Thank you.
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Your design requires that the magnitude of the work done by this
device to be equal to ??, where ?? ? ?, from the initial contact to
the maximum compression of the bumper spring. What is the magnitude
of ?? Important Hint: Δ?, the maximum compression, will change with
the energy dissipation device.
2, Figure 1: Figure 2: Consider the model above for an elastic collision used to design bumpers on cars. Car 1 with the bumper (a spring) has...
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What is the SN2 reaction? How does Br attach to which carbon as
a nucleophile and why? Difference between Unimolecular or
Bimolecular? How NaBr and H2SO4 work in the
reaction? Why Water/Sulfuric Acid/Brine/Sodium
Hydroxide/Na2SO4 in Extraction? What does
each layer have inside in each step of the separation?
Please help. Due to corona, this is a theoretical lab and I am
very confused.
Chapter 16. The Sy2 Reaction: 1-Bromobutane Handout by Dr. Zhiyong Wang CH3CH2CH2CH, OH NaBr, H2SO4 ©Dr. Wang...
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