Question

1.500 University student's exam scores are determined at the end of the semester. Patty scored 850 marks (X) in total out of 1000. The average score for the tests was 725 (u) and the standard deviation was 180 (a). Let's find out how well Patty scored compared to her peers. Using the above data we need to first standardize his score and use the respective 2-table to determine how well he performed compared to his batch mates. To find out the Z score we use the formula: Z score = (x- )/o

Answer 1

This is a normal distribution question with

Mean(u) = 725 Standard Deviation(o) = 180 Since we know that score =

P(x < 850.0)=?
The z-score at x = 850.0 is,

850.0-725.0 180.0

z = 0.6944
This implies that
P(x < 850.0) = P(z < 0.6944) = 0.7563

patty scored better than 75.63% of his batchmates
PS: you have to refer z score table to find the final probabilities.
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