Two point charges are fixed on the y axis: a negative point charge q1 = -29 ?C at y1 = +0.19 m and a positive point charge q2 at y2 = +0.32 m. A third point charge q = +8.4 ?C is fixed at the origin. The net electrostatic force exerted on the charge q by the other two charges has a magnitude of 29 N and points in the +y direction. Determine the magnitude of q2.
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net force=26N= Kq(q2/y2^ 2 + q1/y1^2 );
q2 =(26+ K.q.q1/y1^2).(y2^2/Kq)
=(26 + 9*8.4*26*10^-3 / 0.19^2).(0.31^2 / 9*8.4*10^3)
=1.023*10^-4
=0.1023 mC
net force=26N= Kq(q2/y2^ 2 + q1/y1^2 );
q2 =(26+ K.q.q1/y1^2).(y2^2/Kq)
=(26 + 9*8.4*26*10^-3 / 0.19^2).(0.31^2 / 9*8.4*10^3)
=1.023*10^-4
=0.1023 mC
net force=29N= Kq(q2/y2^2 + q1/y1^2 );
=> 29 = 9*10^9 * 8.4*10^-12 [29/0.19^2 - q2/0.32^2]
=> q2 = +42.97 micro C
net force= 29N= Kq(q1/y1^2 + q2/y2^2 );
here k = 9*10^9
q = 8.4*10^-6 C
q1 = -29*10^-6 C
so
=> 29 = 9*10^9 * 8.4*10^-6 [29*10^-6 /0.19^2 - q2/0.32^2]
=> q2 = +42.97 * 10^-6 C
=> q2 = +42.97 micro C
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