Two point charges are fixed on the y axis: a negative point charge q1 = -29 μC at y1 = +0.16 m and a positive point charge q2 at y2 = +0.34 m. A third point charge q = +8.3 μC is fixed at the origin. The net electrostatic force exerted on the charge q by the other two charges has a magnitude of 24 N and points in the +y direction. Determine the magnitude of q2.
given that
q1 = -29*10^-6 C
q = 8.3*10^-6 C
y1 = 0.16 m
y2 = 0.34 m
force f = 24 N
electrostatic force between two point charges is f = kq1q2/r^2
here
f net = f1+f2
24 = kqq1/y1^2-kqq2/y2^2
k = 9*10^9
kqq2/y2^2 = 9*10^9*8.3*10^-6*29*10^-6/0.16^2-24
kqq2/y2^2 = 84.62-24 = 60.62 N
q2 = 60.62*0.34^2/8.3*10^-6*9*10^9
q2 = 0.09381*10^-3 C
q2 = 93.81*10^-6 C = 93.81 μC
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