Homework Answers
SOLUTION :
As per specific gas law :
PV = m RT
We are dealing with air here.
P = air pressure at given temperature and volume.
V = volume of air = 400 L = 400 / 1000 m^3 = 0.4 m^3
m = mass of air = 5 kg
R = Gas constant for air = 0.287 kPa.m^3 / (kg.K)
T = temperature of air = 25 + 273 = 298º K
So,
P * 0.4 = 5 * 0.287 * 298
=> P = 5 * 0.287 * 298 / 0.4
=> 1069.075 kPa
So, gauge pressure of air = 1069.075 - 97.5 = 971.575 kPa (ANSWER).
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