(a ) ans
the 100ohms , R2 and R3 are in series connection
the resistance R=100+R2+R3=100+3.35+33.5=136.9 ohms
now the resistance R and R1 are parallel connection
the effecitive resistance R"=136.9*0.335/136.9+0.335
=0.3342 ohms..................................(1)
the current at resistance R1=>I1=V/R1=7/0.335=20.9 A
the potential difference at resistance R2=>V2=7*3.35/100+3.35+33.5
=0.2 v
the current at resistance R2=>I2=0.2/3.35=0.1 A
the potential difference at resistance R3=>V3=7*33.5/136.85=1.714 v
the current at resistance I4=1.714/33.5=0.1 A
the potential difference at 100 ohms resistance =>V4=7*100/100+3.35+33.5=5.12 v
thr current at 100 ohms resistance =>I4=V4/R4=5.12/100=0.0512=0.1 A
(b) ans
the resistance R3 and 100 ohms are series connection
resistance R'=33.5+100=133.5 ohms
the resistance R2 and R1 are series connction
resistance R"=0.335+3.35=3.685 ohms
the resistance R" and R' are parallel connection
the effective resistance =3.685*133.5/133.5+3.685=491.95/137.185
=3.59 ohms
the potential difference at resistance R1=>V1=7*0.335/3.35+0.335=0.64 v
the current at resistance R1=>I1=0.64/0.335=1.91 A
the potential difference at resistance R2=>V2=7*3.35/3.685=6.4 v
the current at resistance R2=>I2=6.4/3.35=1.91 A
the potential difference at resistance R3=>V3=7*33.5/133.5=1.76 v
the current at resistance R3=>I3=1.76/33.5=0.1 A
the potential difference at resistance 100 ohms =>V4=100*7/133.5=5.24 v
the current at resistance 100 ohms =>I4=5.24/100=0.1 A
(c) ans
the resistance R1,R2 and R3 are series connection
resistance R'=0.335+3.35+33.5=37.185 ohms
now resistance R' and 100 ohms are in parallel
the effective resistance R"=100*37.185/100+37.185=27.11 ohms
now the current at 100 ohms resistance =>I4=7/100=0.1 A
the potential difference at resistance R1=>v1=7*0.335/37.185=0.0631 V
the current at resistance R1=>I1=0.0631/0.335=0.19 A
the potentail difference at resistance R2=>V2=7*3.35/37.185=0.631 v
the currenrt at resistance R2=>I2=0.631/37.185=0.02 A
the potential difference at resistance R3=>V3=7*33.5/37.185=6.31 v
the current at resistance R3=>I3=6.31/33.5=0.17 A
In the figure below, R_1 = 0.335 Ohm, R_2 = 3.35 Ohm, and R_3 = 33.5...
In the figure below. E = 9.00 V, R_1 = 100 Ohm, R_2 = 500 Ohm, and R_3 = 700 Ohm. (a) What is the equivalent resistance of the three resistors? (b) What is the electric potential across resistance 1? (c) What is the current through resistance 3?
Consider the circuit shown in the figure below.(Assume R_1 = 11.5 ohm and R_2 = 3.50 ohm.) v find the potential difference between points a and b. Find the current in the 20.0-ohm resistor. A
Consider the circuit shown below: R_1 = 670 Ohm R_2 = 190 Ohm R_3 = 780 Ohm R_4 = 690 Ohm E = 6.0 V Calculate the potential difference across R_4. Correct, computer gets: 2.56e+00 V Calculate the power dissipated in R_3
Consider the resistor network shown in the figure below, where R_1 = 1Ohm and R_2 = 8 Ohm. Find the equivalent resistance between points a and b in Figure 26-51. Ohm If the potential drop between a and b is 12 V, find the current in each resistor. I_12 Ohm A I_16 Ohm (upper branch) A I_8 Ohm A I_1 Ohm A i_6 Ohm (lower branch) A
Find the potential difference across each resistor in the figure below. (R_1 = 4.90 Ohm, R_2 = 3.80 Ohm, R_3 = 2.80 Ohm, R_4 = 2.40 Ohm)
In the circuit in the figure below, the batteries have negligible internal resistance. (Take R_1 = 2.40 Ohm, R_2 = 4.35 Ohm, and R_3 = 5.80 Ohm. Find the magnitude of the current in each resistor. Find the magnitude of the potential difference between points a and b. Find the power supplied by each battery. left battery right battery
A battery V = 24.0 volts, a resistor R_1 = 12.0 Ohm and a
resistor R_2 = 4.0 Ohm are wired into a circuit with an ideal
voltmeter connected across R_2. See the figure. What is the reading
of the voltmeter?
A battery V = 24.0 volts, a resistor R_1 = 12.0 Ohm and a resistor R_2 = 4.0 Ohm are wired into a circuit with an ideal voltmeter connected across R_2. See the figure. What is the reading of...
Find the potential difference across each resistor in the figure below. (R_1 = 540 ohm, R_2 = 4.20 ohm, R_3 = 2.80 ohm, R_4 = 2.20 ohm) Delta VR_1 = Delta VR_2 = Delta VR_3 = Delta VR_4 =
In Figures 28.4 and 28.6, let R_1 = 14.0 Ohm, let R_2 = 22.0 Ohm, and let the battery have a terminal voltage of 38.0 V. (a) In the parallel circuit shown in Figure 28.6, to which resistor is more power delivered? R_2 R_1 (b) Calculate the sum of the power (^2R) delivered to each resistor. Calculate the power supplied by the battery (I Delta V). W (c) In the series circuit, which resistor uses more power? R_2 R_1 (d)...
In the figure below, the ideal battery has emf E = 30.0 V, R_1 = R_2 = 12 Ohm, R_3 = R_4 = R_5 = 5.6 Ohm, R_6 = 2.0 Ohm, and R_7 = 1.5 Ohm. (a) What is current i_2? (b) What is current i_4? (c) What is current i_1? (d) What is current i_3? (e) what is current is i_5?