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0.6990 and logio 9 0.9542, use these values and the properties of logarithms to approximate the value. Do not use a calor Giv help eith both
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103) Given 1096 = 0.6990 1030 = 0.9542 109= 109.85 {10,5m + 105; } = 103; +1030 - 0.9542 +0.6990. (10988 = 1.6532] 104) Given

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