[Base Rate Fallacy] Suppose a particular disease has a prevalence of 0.5 % people. A medical test to detect this disease has a false-positive rate of 5 % and diagnoses correctly every person who has the disease. What is the probability that a randomly selected person found to have a positive result actually has the disease? Give your answer to three decimal places.
Ans:
Given that
P(disease)=0.005
P(no disease)=1-0.005=0.995
P(posiitve/disease)=1
P(positive/no disease)=0.05
So,
P(positive)=P(positive/disease)*P(disease)+P(positive/no disease)*P(no disease)
=1*0.005+0.05*0.995
=0.05475
P(disease/positive)=P(positive/disease)*P(disease)/P(positive)
=1*0.005/0.05475
=0.091
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