Homework Answers
5)
Ka = 4.7 x 10^-11
pKa = -log Ka = 10.33
a)
pH = pKa + log [salt / acid]
= 10.33 + log [Na2CO3 / NaHCO3]
= 10.33 + log [0.134 / 0.200]
pH = 10.16
b)
concentration of HCl = 0.0300 / 0.710 = 0.04225
pH = pKa + log [salt - C / acid + C]
= 10.33 + log [0.134 - 0.04225 / 0.200 + 0.04225]
pH = 9.908
c)
concentration of KOH = 0.300 / 0.710 = 0.4225
pH = pKa + log [salt + C / acid - C]
= 10.33 + log [0.134 + 0.4225 / 0.200 - 0.4225]
here buffer fails .
concentration of base remains = 0.2225 M
pOH = -log (0.2225) = 0.65
pH = 13.35
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