Question

Use Matlab

Given: x = [13, 5, 7, 9, 1, 4, 7, 10, 13] Use one 'for loop' to create the matrix y of dimension 5X2, using the index to program the address and the value of each element of y; and y = x' Given, x = [2, 3, 4, 5, 3, 4, 5, 6] Use two 'for loops' to create the matrix of dimension 4X2 Use a while statement to determine when the sum of the numbers in the series 1, 2, 3, 4 is greater than 55. Given A = [2, 9, 4, 5, 9, 7, 8, 6] use a 'for loop' and 'if' statement to set all the values below 4 to 0 in A.

Answer 1

1. Here we can see that difference between each element of first row and second row of matrix x is getting incremented. So, we can implement our code as follows:

x=[1,3,5,7,9];
y=zeros(5,2);
y(:,1)=x;
for i=0:4
y(i+1,2)=x(i+1)+i;
end
y

output:

y =

    1    1
    3    4
    5    7
    7   10
    9   13

2.

A=[2,3,4,5;3,4,5,6];
B=zeros(4,2);
[row col] = size(A);
for m=1:row
for n=1:col
B(n,m)=A(m,n);
end
end
B

output:

B =

   2   3
   3   4
   4   5
   5   6

3.

i=1;
sum=0;
while(sum<=55)
sum=sum+i;
i++;
end
i

This indicates that sum of numbers is greater than 55 after the result i.e. i in the code.

output:

i = 12

4.

A = [2,9,4,5,9,7,8,6];
row = size(A);
for i=1:row
if(A(i)<4)
A(i)=0;
end
end
A

The result would be : A = [0,9,4,5,9,7,8,6]