Question

all of question 2

2 Indoor Climbing (10) Joff climbs up a wall at an indoor climbing gym using an auto belay-device. The auto-belny device exerts an upward force equivalent to the weight of 10kg of mass, in order to quickly take up slack while climbing. Joff weighs 700 N and climbs upward with a constant speed of 0.50 m/s. a) What is his acceleration? b) What force pushes Joll up the wall while he climbs? Why? c) Sketch a (detailed) free body diagram for Joff. d) How much force is he exerting vertically while climbing? (Be sure to include direction!)

Answer 1

a= troetaration V(final mlouty ) - (ulcinitial velocity) time (t) as welocity is - a ² constant V-u veu = uru acceleration a=0 m 2 (6) Tatation Mut fome acting on - as ao Jeff Fret Fret - mx mxoo ce The force acting on Jeff equal to weight , so Jeff should be zerw dauuncuards Fupeward w Fupward 2 roon Chward will be that net formon as weight is I Fupewards dw = 7oon For mg (taking g = 10m2) Fe = loxio loon Fars by jeff Fit le Fore by curto belay FB I weight a Free boely agro- FA+ Fie w Loot Ei= 200 700- 10o = 6oon Four earted by jeff is boon