Question

Suppose that A= | 2 0 -2 1 (1 0 0 0 -1 . Find the eigenvectors of A (a) Eigenvector with respect to the smallest eigenvalue:

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Answer #1

A = [ 2 0 0 7 | -2 1 0 Li 0 - 1 LA-d Il = 0 † 2-0 0 0 1 = (2-1)(1-4) (+)=0 1 -2 1- F1 O -lad | » di = -1, de = 1 ; +3 = 2 AX=OO x=0 q=0 % = a 1 let) T = 7 pa 1-7 I he LO0 6:1. (8) 12 Ooo -2 1-1 Ooi J RREF TI007 s 24 7 Dob131-13 Lo Oo Lw -0 % =0 x= afJ RREF 1 3 - + 4 = 3a k=-6 a a *+62 -0 ota sa v 4-34= 0 h+ 6% =0 x-alld) cas smallest eigenvalue di=- (6) second smallest eig

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