Question

Electrical Engineering Ideal Transformer Question

4. You are given the circuit shown below. Please note the polarities of the currents and voltages at the ideal transformer. The source voltage is 10V RMS. 21 j11 1 1:4 j10N 400 W ell ell + + 1020 -j112 1

Answer 1

Solution- (a) As per dot polarity - = and, as we know if current enters dot on one side then it should leave from the dot on the other side. 6o, 7 / 2 = 42 The renin voltage across terminals A-B, Vth = 10600 T-11_ volts 2 = 10L-30º 51-90° volts Theren in impedence across terminals A-B, 2th = (-j1) // (2+71) = 2.11 |-63.43° 2

for thevenin equivalent circuit - enu I 2h ilon 400 1:4 Vin = 5610 @ عنون 11 < + 712 (C) By applying Kve in loop-1 :- Vth - I, Zth = No 40 Bя «РРчга кус n loop - 2 : - No = - I, Z2 Z2 = 4+jio) on, We know, a ta - Ve="Avi and, 24 12 = 11/4 put these va and I values in eq. ③ 1. (401) = -() 22

Put this vi from eq. ② into eq. ☺ So, - Vth - I zn = I1 22 16 ( 16 51992 $ ( 10 10 + 11663:48) 5 l30º = I1 (3.01 | -6099") 16 ... I = 5 / 1900 3.01 -6.990 Ita 1.65/ -83.00 Any