Question

In the circuit shown in Fig. I, T is an ideal transformer whose turns ratio n/n is 2, where ni and n are the number of turns of the primary winding and the number of turns of the secondary winding, respectively; V is a sinusoidal voltage source whose phasor voltage is 240v2 L45 V; ZI and Z2 are two loads and their impedances are Z1-8Q, Z2-2p. Find phasor current i1, i2 and phasor voltage V1 and V2 Z1 V1 Fig.

Answer 1

K = n_2/n_1 = 1/2 = 0.5 Reffer z_L to primary side z'_2 = z_L/k^2_b = jL/(0.5)^2 z'_2 = j 8 ohm i_1 = V_s/z_1 + z'_2 = 240 squareroot 2 angle 45 degree/8 + j 8 i_1 = 30 angle 0 degree A therefore i_1/i_2 = K i_2 = i_1/K = 30 angle 0 degree/0.5 i_2 = 60 angle 0 degree A V_2 = z_2 i_2 = (j 2) (60 angle 0 degree) V_2 = 120 angle 90 degree V V_2/V_1 = K V_1 = V_2/K = 120 angle 90 degree/0.5 V_1 = 240 angle 90 degree V

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