Question

As shown in the figure, two long, straight current-carrying wires (1 and 2) are attached right angles to a board by wire brackets. The current in wire 1 is 6.73A in the negative y direction and the current in wire 2 is 5.00 A in the positive x direction. The points and are a distance - 0.200 m from both wires. (*) How does the magnitude of the net magnetic field at point A compare to the magnitude of the net magnetic field at point ? OBA 3. (1) Determine the magnitude of the net magnetic field at points A and B. point point of the brackets holding wire 2 are removed, what will happen to wire 2) It will rotate di Nothing will happen

Answer 1

@ into the page ④ out of the page. A B B2 TH B and Be are magnetic field of due to I, and Iz respectively, Il I= 6.73A) and I2 =5A Ir=0.2m Bi is same at both paint A and B due to symmetry. By is also same at bath A and B due to symmetry At point A Bi and Be are opposite direction but at point B, B and Be are in same alorection. So, magnitude of net magnetic field at point B is greater than at A. .. Bp > BA » BA <B₂) At paint A. 492107 구 6.73. T A. B = Moll 20r 20x0.2

» /B,= 6.73x1067 By Mo Iz 47X165 = T 208 2x0.2 > B2 B2 = 5x10rb .. magnitude of net magnetic field is BA= B, B2 = (6.73x10-65x166). BA= 1.73x1067 At point B. magnitude of net magnetic field at B is BB = BitB₂ >> Be= (6.73x10675716697 đó B Be= 11.73x1067 Iz For xco force on aire 2 is along ty direction and elu for aso force on wire 2 is along -Y direction, YI So, werez rotates clockwise if bracket holders are removed.