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A snack size bag of m&ms candies is opened. Inside, there are 12 red candies, 12...

A snack size bag of m&ms candies is opened. Inside, there are 12 red candies, 12 blue, 7 green, 13 brown, 3 orange, and 10 yellow. Three candies are pulled from the bag in succession, without replacement. What probability that the first two candies drawn are green and the third is red? 12+12+7+13+3+10=57 7/57x6/56x12/55 =504/175560 How did they get 3/1045 as the final answer?

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red → 12 blue → 12 3 →10 Total →57 candies 5 canelleauil wii 6 56 12 5 S 57 56 55 504 3 X16 8 3 1チ5560 1045x168 1015

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