Problem 18.46
An engine receives 790J of heat from a hot reservoir and gives off 450J of heat to a cold reservoir.
Part A
What is the work done?
ANSWER:
W = | J |
Part B
What is the efficiency of this engine?
ANSWER:
e = |
PART-1
W =Qh-Qc
W=790-450
W=340J
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PART-2
efficency = (Qh-Qc)/Qh
eff= 790-450/790
efficiency =0.4303
efficiency=43.03%
apply Work Done W = dQ-dU
W = 790-450 = 340 J -<<<<<<<<<<<<,answer
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efficiency e = 1-T2/T1
e = W/Q
e = 340/790
e = 43.03 % effiecint -<<<<<<<<<<<<,answer
Problem 18.46 An engine receives 790J of heat from a hot reservoir and gives off 450J...
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