Answer:
2)
n=500, x= 150, C= 90%, = 0.10, P=0.27
a)
Ho: P 0.27
H1: P > 0.27
b)
Calculate test statistics
z = 1.510994713
test statistics = 1.51
Calculate P-Value
P-Value = 1 - P(z < 1.51)
find P(z < 1.51) using normal z table
P(z < 0.1.2659) =0.9345
P-Value = 1 - 0.9345
P-Value = 0.0655
since (P-Value = 0.0655) < ( = 0.10)
null hypothesis (Ho) is rejected.
3)
= 11, n=14, =10.5, S2= 0.56, = 0.49
=5% = 0.05
Ho: 0.49
H1: > 0.49
14.857
Test statistics= 14.857
Calculate Critical value using X2 table with
df = n-1 = 14-1 = 13 and = 0.05
We get critical value as
X2 Critical value =22.362
Since (Test statistics= 14.857) < (X2 Critical value =22.362)
it is concluded that the null hypothesis is not rejected.
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