Do AO Do DO Enter the Boolean algebra expression for the circuit seen in the Logisim...

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Answer 1

Answer #1

Answer:

W = ~(D ∧ (((~AV(A ∧(B∧C)))V(~BV(A∧~(BVC)))))

I have lablled the diagram for your understanding. All inverted V symbols( ∧) refer logical and

A AV(A (BAC) AO B Do AVA (BAC))V(-BV(A^(BVC)) BV(A (BVC)) D. BVC) BVC AA (BVC) A (BAC) BAC (Ow DO D(C-AV(A (B C)))V(~BV(A^~(

Answer 2

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