Solution) m1 = 48 kg
m2 = 2 kg
u1 = u2 = 1.20 m/s
V = ?
Applying conservation of momentum
(m1)(u1) + (m2)(u2) = (m1)(V1) + (m2)(V2)
(48)(1.20) + (2)(1.20) = (48)(V1) + (2)(0)
=> 60 = (48)(V1)
= > (V1) = (60)/(48) = 1.25 m/s
V1 = 1.25 m/s
Option(4) 1.25 m/s in the same direction as he was riding .
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