Question

A C b B a Note: Triangle may not be drawn to scale. Suppose mZA 45 degrees and b = 6. Find: a. CE m/B degrees Give all sides in exact form. Give angles in degrees

Answer 1

Soluno - we know that sum is 180° .. LA+B+<C = 180* → 28 = 180º-go® - 45€ 712B= 450 IA 450 1 6=6 C 90° 450 a Now " B tan 45º = b a tan 45° = 6 blo a a= Hos tan 45° a= 6 π Using pythagora ras theorem c2= a?+ b² Jaz. +6² 62 +6692 7 C C36+36 - + C= 8.485 = 8.5 cang 72

Ans:10) cot (30) cot30* - COS 30* sin 30 we know that COS 30® = and Sin 30º = -1CY cot (300) = fotolar =V3 = =cot(30%) = 13 • CSC (60°) = -1 U [:: sin60°=13 sim (60°) ulast 2 CSC(60) citing

tan 1459) = sin 45° Cos 45 ge knoo that, sin45°= \ || and cos 45º = 2 tan 45º = 하 슈 2 = 1 IR 키 tan4g = 1

Answer 2

SOLUTION :

Since, angle A = 45º and angle C = 90º

so, angle B = 180 - (90 + 45) = 45º (ANSWER).

Side b = c cos (45) = 6 (given)

So, side a = c cos (45) = 6 (ANSWER)

Side c = b / cos (45) = b / (1/√2) = 6 √2  (ANSWER)

10.

cot(30) = cos(30) / sin(30) = (√3 / 2) / (1 / 2) = √3 (ANSWER).

csc(60) = 1 / sin(60) = 1 / (√3/2) = 2 / √3 (ANSWER).

tan(45) = sin(45) / cos(45 = (1 / √2) / (1 / √2) = 1 (ANSWER).