given
d = 0.4*10^(-9) m
L = 1.5*10^(-9) m
the potential energy of the electron
U = V1 * q + V2 * q
U = kQcos/L +
kQcos
/L
U = 2(kQcos /L )
where cos =
0.96 { as tan
= d/L}
U = 2(9*109 * 1.6*10-19* 0.96 * 1.6*10-19 /1.5*10-9)
U = 1.536 *10-19 J
answer
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