Question

please, do the calculation

the total volume should be 2 ml

electroless plating solution 28.2 0.188 PdCl2 (mm) Na EDTA (M) NH,OH (M) NH NH2 (mm) volume (mL) 0.11 3.17 11 4.5 15 ( 2 of poly(vinylpyrrolidone) (PVP) (My 1.3 106, Sigma-Aldrich). and 0.7 mL of ethanol was prepared and electrospun using a 23 gauge needle with a flow rate of 0.3 mL/h at an applied potential of 7 kV and a collection distance of 5 cm. The collected composite nanofibers were kept in the air overnight, followed by calcination in a muffle furnace at 500 °C for 3 h to remove PVP and generate a TiO2 nanofibrous membrane. 2.2. Electroless Plating of Palladium. To coat the TiO2 nanofibers with palladium, the Tio, nanofibrous membrane was

Answer 1

Electroless plating solution : ( for pencil marked solution )

(as per provided information , and asked question)

Total Volume : 2 mL

1.

15 mM PdCl₂ : 15*10^-3 mol/L

      for 2 mL : 0.002 L *15*10^-3 mol/L = 3*10^-5 mol

     PdCl2 molar mass : 177.33 g/mol

177.33 g/mol*3*10^-5 mol = 5.32*10^-3 g     ( 1g = 1000 mg )

      Thus , amount of PdCl₂ required : 5.32 mg

2.

0.11 M Na₂EDTA : 0.11 mol/L

   for 2 mL : 0.002 L *0.11 mol/L = 2.2*10^-4 mol

Na₂EDTA molecular weight of 336.2 g/mol.

336.2 g/mol*2.2*10^-4 mol = 0.0739 g

   Thus , amount of Na₂EDTA required : 0.074 gm

3.

3.17 M NH₄OH

for 2 mL : 0.002 L *3.17 mol/L = 6.34*10^-3 mol

Lab solution : molarity of 56.6% (w/w) Ammonium Hydroxide is equal to 14.534 M .

Thus Vol. Needed : 6.34*10^-3 mol / (14.534 mol/L) = 4.36*10^-4 L = 0.44 mL

(adjust according available NH₄OH solution in your Lab)

4.

11 mM H₂N-NH₂: 11*10^-3 mol/L (hydrazine )

      for 2 mL : 0.002 L *11*10^-3 mol/L = 2.2*10^-5 mol

    H₂N-NH₂ molar mass : 32 g/mol

      Thus , amount of H₂N-NH₂ required : 0.704 mg

H₂N-NH₂ density : 1.02 g/ml

= 0.704*10^-3 g / 1.02 g/ml = 6.90*10^-4 mL

    Thus 0.69 uL (micro L) .

Mix all these and add required amount of DI-water to make final Volume: 2mL.