The rate law for the decomposition of N2O5 is rate = k[N2O5] If k = 1.0...
The rate law for the decomposition of N2O5
is
rate = k[N2O5]
If k = 1.0 x 10-5 s-1, what is the
reaction rate when the N2O5 concentration is
0.0091 mol L-1?
2.The decomposition of acetaldehyde, CH3CHO, was
determined to be a second order reaction with a rate constant of
0.0771 M-1 s-1. If the initial
concentration of acetaldehyde is 0.301 M , what will the
concentration be after selected reaction times?
a. What will the CH3CHO concentration be after 30.0 minutes?
b. What will the CH3CHO concentration be after 180 minutes?
Homework Answers
![1) Rate law: rate *[N2O,] we have k=1.0×10-5 s-1 [Ν,0,1- Thus, 0.0091 mol L-1 rate =小1,0.] = (1.0×10-5 s-1)(0.0091 moll = 9.1](http://img.homeworklib.com/questions/c2ddf440-50cb-11ec-96bb-893ee3fbff77.png?x-oss-process=image/resize,w_560)
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The rate law for the decomposition of N2O5
is
rate = k[N2O5]
If k = 1.0...
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s-1.
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