Question

Determine the limiting reagent (rl), excess reagent (re), theoretical yield (rt) for Mg3N2, if 60.0g of Mg and 37.5g of N2 react according to the following balanced reaction. 3 Mg + N2 → Mg3N2

Answer 1

Answer: 3 Mg + Mg ₂ N2 N2 60 g 37.5 g ( 2.5 miles) (= 1-34 moles) According to Stoichiometry; I mole of No requires 3 moles of Mg >) 1. 34 moles of Na will require 4.02 moles of Mg But We have only 2.5 moles of Mg. Therefore, Limiting Reagent is Mg. excess reagent Acording to stoichio medsy 2 3 moles of Mg will give of Mg 3 Na. M will give 0.83 moles of Mg3 N2 . Na I mole - 2.5 moles 0.83 moles of Mg3 Na 0.83 x 100.9 83.7 g Mga Na g Mga Na 83.79 =) Theoretical Yield of Mg ₂ N2

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