1. If 142 mg of triphenylmethanol (limiting reagent) reacts with excess Hbr, what mass of triphenylmethyl...
1. If 142 mg of triphenylmethanol (limiting reagent) reacts with excess Hbr, what mass of triphenylmethyl bromide should be formed? (theoretical yield)
0.0255 mol
2. If 110 mg of triphenylmethyl bromide is actually formed, what is the percent yield of the product?
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1. If 142 mg of triphenylmethanol (limiting reagent) reacts with
excess Hbr, what mass of triphenylmethyl...
please calculate the theoretical yield and the percent yield!! RESULTS Mass of triphenylmethanol -__0.10 9 Theoretical...
please calculate the theoretical yield and the percent
yield!!
RESULTS Mass of triphenylmethanol -__0.10 9 Theoretical yield triphenylmethyl = bromide Mass of product = 0.149 (triphenylmethyl bromide) 9 Percent yield Melting point of product = 150.3 °C CALCULATIONS e triphenylmethanol x Imol triphenylmethanol x Imol triphenylmethyl bromide v 323.23g triphenylmethylbromide 260.33g triphenylmethanol 1 mol triphenyl methanol 1 mol triphenylmethyl bromide
please help!! thank you A sample of 42.5 g of Mg metal reacts with 1.50 L...
please help!! thank you
A sample of 42.5 g of Mg metal reacts with 1.50 L of 6.00 M HCl(aq) to form H2 gas. Mg (s) + 2 HCl(aq) MgCl2 (aq) + H2 (g) What is the limiting reagent? Limiting Reagent Enter your answer here How many mol of H2 gas are formed? Mol H2 = Enter your answer here mol If the H2 gas is produced at 35°C and 765 mmHg what is the volume of the gas? Volume...
2. What is the limiting reactant when 126 g of Ag reacts with 142 g of HNO3? What is the heoretical yield in gra...
2. What is the limiting reactant when 126 g of Ag reacts with 142 g of HNO3? What is the heoretical yield in grams of AgNO3? Ag(s) + HNO3 (aq) → AgNO3(aq) + NO(g) + H2O) 2. What is the limiting reactant when 126 g of Ag reacts with 142 g of HNO3? What is the theoretical yield in grams of AgNO3?! Ag(s) + HNO3 (aq) → AgNO3 (aq) + NO(g) + H2O)
Question 7 4 pts What is the limiting reagent when 0.7541 g of phosphorus reacts with...
Question 7 4 pts What is the limiting reagent when 0.7541 g of phosphorus reacts with 2.409 g of chlorine? Pals) + 6C12(8) 4 PC1300 P4 Cl2 PCIE > Question 8 4 pts Calculate the theoretical yield of phosphorus trichloride (ing) when 0.7541 g of phosphorus reacts with 2.409 g of chlorine. (Use 137.38 mol for the molar mass of phosphorus trichloride). Pals) + 6C12(e) 4 PC136
A 0.191g piece of solid aluminum reacts with gaseous oxygen from the atmosphere to form solid...
A 0.191g piece of solid aluminum reacts with gaseous oxygen from the atmosphere to form solid aluminum oxide. In the laboratory, a student weighs the mass of the aluminum oxide collected from this reaction as 0.199 g. The 0.191g solid aluminum is the _____. A) percent yield, B) excess reagent, C) limiting reagent, D) actual yield, E) theoretical yield The 0.199g aluminum oxide is the ______. A) actual yield, B) percent yield, C) limiting reagent, D) theoretical yield, E) excess...
Question text A limiting reagent is Choose...consumed completelyleft over in excess during a chemical reaction, and...
Question text A limiting reagent is Choose...consumed completelyleft over in excess during a chemical reaction, and it Choose...decreasesincreases the possible amount of product that can be formed. Question 2 Not yet answered Points out of 1 Flag question Question text A student used 7.15 g of CaCl2 and 9.25 g of K2CO3 to make CaCO3. The reaction is: K2CO3(aq) + CaCl2(aq) = CaCO3(s) + 2KCl(aq). Based on the masses of the two reactants given, the limiting reagent is Choose...CaCl2K2CO3 ....
What is the theoretical yield and the percent yield of this Grignard reaction which converts phenyagnesiumbromide...
What is the theoretical yield and the percent yield of this
Grignard reaction which converts phenyagnesiumbromide into
triphenylmethanol?
actual yield of final product is 0.00958grams
also would the limiting reagent be magnesium??
Reagent Amountured maghlesinm 51.4 mg Bromo benzene 4.10.2 2 mg methyl benzoatel 141.5 mg
A 0.241 g piece of solid aluminum reacts with gaseous oxygen from the atmosphere to form...
A 0.241 g piece of solid aluminum reacts with gaseous oxygen from the atmosphere to form solid aluminum oxide. In the laboratory, a student weighs the mass of the aluminum oxide collected from this reaction as 0.204 g. Part 1 The 0.241 g solid aluminum is the __________. --Choose one: A. limiting reagent B. theoretical yield C. percent yield D. excess reagent E. actual yield Part 2 The 0.204 g aluminum oxide is the __________. --Choose one: A. limiting reagent...
plz show work Chapter 7 Yield Calculations <Chapter 7 Yield Calculations Simulation Limiting Reagent and Theoretical...
plz show work
Chapter 7 Yield Calculations <Chapter 7 Yield Calculations Simulation Limiting Reagent and Theoretical Yield with Masses 7 of 13 You are provided with 5.80 g of S02 to react with 2.45 g of O. Indicate your theoretical yield by completing following statemonts Match the chemical formulas and amounts in the left column to the appropriate blanks in the sentences on the right. Make certain each sentence is complete before submitting your answer. View Available Hint(s) Reset Heip...
answer it all please BS132 Experiment 3 2018-2019 The limiting reagent is the reagent which will...
answer it all please
BS132 Experiment 3 2018-2019 The limiting reagent is the reagent which will completely react and so iIs excess. It will therefore be the reagent for which a lower number o present. Compare the respective molar proportions of the reagents used A and B above] and deduce which is the limiting reagent not in f moles are Igiven by Limiting reagent = 1 mark Scale of reaction (i.e. number of moles of limiting reagent used) - mol...
please calculate the theoretical yield and the percent
yield!!
RESULTS Mass of triphenylmethanol -__0.10 9 Theoretical yield triphenylmethyl = bromide Mass of product = 0.149 (triphenylmethyl bromide) 9 Percent yield Melting point of product = 150.3 °C CALCULATIONS e triphenylmethanol x Imol triphenylmethanol x Imol triphenylmethyl bromide v 323.23g triphenylmethylbromide 260.33g triphenylmethanol 1 mol triphenyl methanol 1 mol triphenylmethyl bromide
please help!! thank you
A sample of 42.5 g of Mg metal reacts with 1.50 L of 6.00 M HCl(aq) to form H2 gas. Mg (s) + 2 HCl(aq) MgCl2 (aq) + H2 (g) What is the limiting reagent? Limiting Reagent Enter your answer here How many mol of H2 gas are formed? Mol H2 = Enter your answer here mol If the H2 gas is produced at 35°C and 765 mmHg what is the volume of the gas? Volume...
2. What is the limiting reactant when 126 g of Ag reacts with 142 g of HNO3? What is the heoretical yield in grams of AgNO3? Ag(s) + HNO3 (aq) → AgNO3(aq) + NO(g) + H2O) 2. What is the limiting reactant when 126 g of Ag reacts with 142 g of HNO3? What is the theoretical yield in grams of AgNO3?! Ag(s) + HNO3 (aq) → AgNO3 (aq) + NO(g) + H2O)
Question 7 4 pts What is the limiting reagent when 0.7541 g of phosphorus reacts with 2.409 g of chlorine? Pals) + 6C12(8) 4 PC1300 P4 Cl2 PCIE > Question 8 4 pts Calculate the theoretical yield of phosphorus trichloride (ing) when 0.7541 g of phosphorus reacts with 2.409 g of chlorine. (Use 137.38 mol for the molar mass of phosphorus trichloride). Pals) + 6C12(e) 4 PC136
What is the theoretical yield and the percent yield of this
Grignard reaction which converts phenyagnesiumbromide into
triphenylmethanol?
actual yield of final product is 0.00958grams
also would the limiting reagent be magnesium??
Reagent Amountured maghlesinm 51.4 mg Bromo benzene 4.10.2 2 mg methyl benzoatel 141.5 mg
plz show work
Chapter 7 Yield Calculations <Chapter 7 Yield Calculations Simulation Limiting Reagent and Theoretical Yield with Masses 7 of 13 You are provided with 5.80 g of S02 to react with 2.45 g of O. Indicate your theoretical yield by completing following statemonts Match the chemical formulas and amounts in the left column to the appropriate blanks in the sentences on the right. Make certain each sentence is complete before submitting your answer. View Available Hint(s) Reset Heip...
answer it all please
BS132 Experiment 3 2018-2019 The limiting reagent is the reagent which will completely react and so iIs excess. It will therefore be the reagent for which a lower number o present. Compare the respective molar proportions of the reagents used A and B above] and deduce which is the limiting reagent not in f moles are Igiven by Limiting reagent = 1 mark Scale of reaction (i.e. number of moles of limiting reagent used) - mol...
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