Question

A 0.191g piece of solid aluminum reacts with gaseous oxygen from the atmosphere to form solid aluminum oxide. In the laboratory, a student weighs the mass of the aluminum oxide collected from this reaction as 0.199 g.

The 0.191g solid aluminum is the _____.

A) percent yield, B) excess reagent, C) limiting reagent, D) actual yield, E) theoretical yield

The 0.199g aluminum oxide is the ______.

A) actual yield, B) percent yield, C) limiting reagent, D) theoretical yield, E) excess reagent

The gaseous oxygen is the _______.

A) actual yield, B) theoretical yield, C) excess reagent, D) limiting reagent, E) percent yield

What is the percent yield of this reaction? ______%

Answer 1

Equation: 4A1 + 30, — 2A1,03 The 0.191 g solid aluminum is the limiting reagent The 0.199g aluminum oxide is the actual yield The gaseous oxygen is the excess reagent No of moles of A1,03 produced = 0.191 3x- 1911 mol Al 2 mol A1,93 13*26.98 g 4mol A1 = 0.00354 mol A1, 101.96g Theoretical yield of A1,9; = 0.00354 mol A1,0,*- 1 mol A1,03 = 0.361 g Actual yield of A1,9, = 0.199 g actual yield Percent yield = *100% theoretical yield 0.199 g %100% 0.361 g = 55.1% 55%