Question

A 0.241 g piece of solid aluminum reacts with gaseous oxygen from the atmosphere to form solid aluminum oxide. In the laboratory, a student weighs the mass of the aluminum oxide collected from this reaction as 0.204 g.

Part 1 The 0.241 g solid aluminum is the __________.

--Choose one: A. limiting reagent

B. theoretical yield

C. percent yield

D. excess reagent

E. actual yield

Part 2 The 0.204 g aluminum oxide is the __________.

--Choose one: A. limiting reagent

B. theoretical yield

C. excess reagent

D. percent yield

E. actual yield

Part 3 The gaseous oxygen is the __________.

--Choose one: A. theoretical yield

B. actual yield

C. percent yield

D. limiting reagent

E. excess reagent

Part 4See Hint What is the percent yield of this reaction?

______________%

Answer 1

Wiben soi aluminium 3 mol no Oxygen (96 g. So, & moles i... 108 to form 2 moles 2 Seid Alreacts with Or the reaction is AA1+30 - 2A1₂03 2x102 g. 4X279 3x32g solid beide noles i... 108 g solid Al reats with geneous m 2 moles of Al₂O3 line. 204g. Al2O3) from 108 g Al, Al2O3 formed 204g. "0.241 g Al, " " 204 x 0.214 g 108 - 0.455 gi So, the theoritical viel of Ablz's 0.445 g. But actually Al₂O3 formed o. 204 9. actual yield x200 the percent yield of the reation theoritical yield 0.201 100 0.455 Porta - 44.83% :. The percent yield of the reaction 94.83% Post 1 0.241 g solid Al is the limiting reagent (A) port? Tose 6.2849 Aluminium acide'n the actual yield (E) port3 Here gaseous coryger is the excers reagent (E) Here in air huge amount of sygen available (the 20% of the total air have O2). So, O must be excess reagent. For that 0.241g Al 'n limiting reagent.