When exposed to air, aluminum metal, Al, reacts with oxygen, O2, to produce a protective coating of aluminum oxide, Al2O3, which prevents the aluminum from rusting underneath. The balanced reaction is shown here: 4Al+3O2→2Al2O3 In Part A, we saw that the theoretical yield of aluminum oxide is 1.90 mol . Calculate the percent yield if the actual yield of aluminum oxide is 1.18 mol .
Here is the solution of your question. If you have any doubt or need any clarification please comment in comment box and will definitely resolve your query. If you find useful please upvote it. Thanks in advance.
When exposed to air, aluminum metal, Al, reacts with oxygen, O2, to produce a protective coating...
When exposed to air, aluminum metal, Al, reacts with oxygen, O2, to produce a protective coating of aluminum oxide, Al2O3, which prevents the aluminum from rusting underneath. The balanced reaction is shown here: 4Al+3O2→2Al2O3 a. What is the theoretical yield of aluminum oxide if 1.60 mol of aluminum metal is exposed to 1.50 mol of oxygen?
Aluminum forms a layer of aluminum oxide when exposed to air which protects the bulk metal from further corrosion, 4Al(s) + 3O2(g) → 2Al2O3(s). ΔG° for this reaction is ___________ and this reaction is ____________ . ΔG°f (kJ/mol) Al(s) 0 O2(g) 0 Al2O3(s) -1576.4 Select one: a. 0 kJ/mol; at equilibrium b. 3152.8 kJ/mol; spontaneous c. 3152.8 kJ/mol; nonspontaneous d. -3152.8 kJ/mol; spontaneous e. -3152.8 kJ/mol, nonspontaneous
Oxygen gas reacts with powdered aluminum according to the reaction: 4Al(s)+3O2(g)→2Al2O3(s) What volume of O2 gas (in L), measured at 775 Torr and 23 ∘C , completely reacts with 52.1 g of Al?
Oxygen gas reacts with powdered aluminum according to the reaction: 4Al(s)+3O2(g)→2Al2O3(s) What volume of O2 gas (in L), measured at 782 Torr and 29 ∘C , completely reacts with 52.6 g of Al? (in L)
Oxygen gas reacts with powdered aluminum according to the reaction: 4Al(s)+3O2(g)→2Al2O3(s) What volume of O2 gas (in L), measured at 774 Torr and 29 ∘C , completely reacts with 52.0 g of Al? (answer in Litres)
X 1. Aluminum reacts with oxygen to produce aluminum oxide 4 Al(s) + 3 O2(g) + 2 Al2O3(s) IF 3.0 moles of Alreact with excess O2, how many moles of AlzO3 can be formed? a) 1.0 mol b) 1.50 mol c) 3.0 mol d ) 4.0 mol e) 4.5 mol 10. What is the log of 5,400.05? a) 3.07 b) 3.37 c) 3.73 d) 37.32 e) 37.23 Short Answer Questions (True or False)
Oxygen gas reacts with powdered aluminum according to the following reaction: 4Al(s)+3O2(g)?2Al2O3(s). What volume of O2 gas, measured at 793 mmHg and 28 ?C, is required to completely react with 53.5 g of Al? Express the volume in liters to three significant figures.
Oxygen gas reacts with powdered aluminum according to the reaction: 4Al(s)+3O2(g)→2Al2O3(s) Part A What volume of O2 gas (in L), measured at 762 Torr and 32 ∘C , completely reacts with 52.1 g of Al?
Oxygen gas reacts with powdered aluminum according to the reaction: 4Al(s)+3O2(g)→2Al2O3(s) Part A What volume of O2 gas (in L), measured at 771 mmHg and 34 ∘C, is required to completely react with 51.9 g of Al?
(a) Oxygen gas reacts with powdered aluminum according to the following reaction: 4Al(s)+3O2(g)→2Al2O3(s) What volume of O2 gas, measured at 771 mmHg and 35 ∘C, is required to completely react with 54.1 g of Al? (b) Automobile air bags inflate following a serious impact. The impact triggers the following chemical reaction. 2NaN3(s)→2Na(s)+3N2(g) If an automobile air bag has a volume of 12.2 L , what mass of NaN3 (in g) is required to fully inflate the air bag upon impact?...