Oxygen gas reacts with powdered aluminum according to the reaction: 4Al(s)+3O2(g)→2Al2O3(s) What volume of O2 gas...

Question

Question

Oxygen gas reacts with powdered aluminum according to the reaction:
4Al(s)+3O2(g)→2Al2O3(s)

What volume of O2 gas (in L), measured at 782 Torr and 29 ∘C , completely reacts with 52.6 g of Al? (in L)

Answer 1

Answer #1

mol Al- 52.6 se 27 - 1.948 mol mol O2 = 3 2 x 1.946= 1.461 mol O2 Voz - ART = (1.461)x (0.0921) (273+29) Vo = 35.2 L 35.2

Answer 2

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