Oxygen gas reacts with powdered aluminum according to the following reaction: 4Al(s) + 3O_2(g) rightarrow 2Al_2O_3(s)...

Question

Question

Answer 1

Answer #1

From the reaction given in question we can say that

4 moles of Al reacts with 3 moles of O2.

so 108 g of Al react with 3 moles of O2.

so 52.2g Al would react with 1.45 moles of O2.

volume occupied by O2:-nRT/P

n=1.45, R=0.082, T=307K, P=760mm Hg=1atm

volume=36.5 L

Answer 2

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