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point ces 2 (10 points) An elevator cabin has a mass of358.1 kg, and the combined mass of the people inside the cabin is unknown. The cabin is pulled upward by a cable, when the elevator is at rest, the tension in the cable is 5167.54 N, what is the combined mass of the people inside cabin? When the elevator accelerates downward, the tension in the cable is 4000 N, What is the acceleration of the elevator?
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Answer #1

given

M = 358.1 kg

tension = m g = 5167.54 N

T = 4000 N

m g = 5167.54 N

m = 527.3 kg

T = ( M + m ) ( a + g )

4000 = ( 358.1 + 527.3 ) ( a + 9.8 )

a = - 5.28 m/sec2

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