Question

Discuss how a parallel plate capacitor (area A and separation d) stores its energy in between its plates in terms of the E-field volume energy density. Calculate the potentials across (V), the charges on (Q), and the total potential energy stored (U), by the capacitances arranged in the circuit which are attached to a 10 V power supply (1u=1x10^6).

27uF C3 I 12uF 12uF! 10V 12uF

Answer 1

Solution i we know Energy stored in capaciter це си? If it is a parallal plate capacitor then. ca est So u= Ź tot uz hose. V= Edd u= t CA x Elde - u = 1 to E² (volume) u l to E² = Energy density ? Ars Past (6) To find Equivalent capacitance volume Iris Gz f CG are in series. Ceq=12x12 1 12+12 = 6 per ♡ Eq. Of ci) is in paraltal with a i 12+6 =18 HF

m) Eq. of lig is in series with = 10.8 27x18 27+18 HF Eq. capacitance of circuit is 2018 HF. Total charge from battery @acogu = 10.8 x 10 = 108 coulomb. Total Energy consumed by circuit = 2 Coque = 6 x 10.8 X 10X10 u= 540 Joule