Question

In AABC, AB = AC and BC = 6 cm. D is a point on the side AC such that AD = 5 cm and CD = 4 cm. Show that ABCD – AACB and henc

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Answer #1

5 AD=5 o BAB=AC BC-6 CD=Y A B =9=AC Y u B 6An A B CD & DA CB common cingle = LC-2 C B Side ratio > DC - 4 ВС 63 & BC-6=2 q 3 z Siches ratio are same for temo of them ABIf you are satisfied with the solution, can upvote ? ?

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Kindly answer the question neatly. Thanks. In AABC, AB = AC and BC = 6 cm....
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