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Q1) Using AW method compare between the following alternatives: (6 marks) Alt. F.C. Operating and Income at the Annual S.V. Useful life i. maintenance nd end of 2 year Income А 35000 0 3500 2800 7000 8 8% B 32000 1500 4700 2500 0 8%

Q1) Using AW method compare between the following alternatives: (6 marks) Alt. F.C. Operating and Income at the Annual S.V. Useful life i. maintenance nd end of 2 year Income А 35000 0 3500 2800 7000 8 8% B 32000 1500 4700 2500 0 8% 

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Answer #1

Answer: Select Alternative B

Annual Worth of Alternative A is -2109.90

Annual Worth of Alternative B is -1237.66

Explanation:

Compute Annual Worth

Alternative A

AW(A) = -35000 * (A/P, 8%, 8) + 3500 * (P/F, 8%, 2) * (A/P, 8%, 8) + 2800 + 7000 * (A/F, 8%, 8)

Compute (A/P, i%, n) using [i * (1 + i)n] / [(1 + i)n - 1]

(A/P, 8%, 8) = [0.08 * (1 + 0.08)8] / [(1 + 0.08)8 - 1] = [0.08 * (1.08)8] / [(1.08)8 - 1]

                    = [0.08 * 1.8509] / [1.8509 - 1] = 0.1740

Compute (P/F, i%, n) using (1 + i)(-n)

(P/F, 8%, 2) = (1 + 0.08)(-2) = (1.08)(-2)= 0.8573

Compute (A/F, i%, n) using i / [(1 + i)n - 1]

(A/F, 8%, 8) = 0.08 / [(1 + 0.08)8 - 1] = 0.08 / [(1.08)8 - 1] = 0.08 / [1.8509 - 1] =0.0940


AW(A) = (-35000 * 0.1740) + (3500 * 0.8573 * 0.1740) + 2800 + (7000 * 0.0940) = -2109.90

Annual Worth of Alternative A is -2109.90

Alternative B

AW(B) = [-32000 + 4700 * (P/F, 8%, 2)] * 0.08 - 1500 + 2500

           = [-32000 + (4700 * 0.8573)] * 0.08 - 1500 + 2500

           = -27970.69 * 0.08 - 1500 + 2500 = -1237.66

Annual Worth of Alternative B is -1237.66

Annual Worth of Alternative B is higher.

Select Alternative B


answered by: Bhargav Agravat
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Q1) Using AW method compare between the following alternatives: (6 marks) Alt. F.C. Operating and Income at the Annual S.V. Useful life i. maintenance nd end of 2 year Income А 35000 0 3500 2800 7000 8 8% B 32000 1500 4700 2500 0 8%
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