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Q1: In a completely randomized experimental design, 7 experimental units were used for each of the 5 different levels of treatments: Degrees of Freedom Mean Square Source of Variation Sum of Squares Between Treatments Error (Within 22.3 Treatments) 30.5 (A) (0) (G) 10 Total (0) a. Complete the above ANOVA table by computing the values of (A) to. b. At Q -0.05, test the hypothesis that the population treatment means are all the same. Critical Value - 2.69

Answer 1

Solution Experimental unit used= = 7 No of levels of treadments = R=5 & Total Units used =N=nk=7*5=35. 80.5-29.3 =589 (B) Degree of freedoro for treatments R-1=51=Y 1A2 Sum of square of between (C) Degree of freedom for within = Nok= 35-5=30 101 Degree of freedom for Total= N-1= 35-1234 Mean Square {= 58.214 14055 99.313. 7•4333 14.55 7.43333 G 1) Elf = -1.9574 aur equal. Nell Hylother's & Ho: All treatment means Alternative Hypother's, Hi : At least tuvo different means are

Since 1.96 IS F - (G) = 1.957 Critical value = But Fenite 9.69 fair to Reject Sincere F L Frente Sol to Rejaca Ho Conclusion : Do not Reject Ho, all Ho, all theatreents are equal data does any sufficient evidence againust means and nod brovide Hor mean Source of varication Sum of sauce Degret of feetcom sauale 14.55 11-9574 니 Between reeatments 58.2 22.3 3 o 17.43333 Error [within Treatments] Total 80.5 34
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