A 0.2 kg object is suspended from a spring with a spring constant of k=10 n/m....
Homework Answers
given
spring constant K = 10 N/m
amplitude = A = 0.08 m
mass = 0.2 kg
potetial of a body in SHM = PE = 0.5*K*x^2
x = displacement of the body from the mean
position
here x = 0.08 m
PE = 0.5*10*0.08^2 = 0.032 J <-------answer
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0.2 kg object is suspended from a spring with a spring constant of
k=10 n/m....
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