Question




7.11 A rectangular loop carrying 10 A of current is placed on z = 0 plane as shown in Figure 7.32. Evaluate H at (a) (2,2,0)
10 A 0 FIGURE 7.32 Rectangular loop of Problem 7.11.
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Answer #1

Answer:

Given that Z = 0

H = 1 + 2 + 3 + 4

H = H2

H = 271 +H2+H4

a)

( 2 , 2 , 0 )

H1 (cosa2 – cosa1) ao

  H1 = ਜੋਰ ਕਰ

  H:= (2* 147

H = 1 2- 、 104

H 5.2 1. 5 - 5 laz = 1.9642A/m V2 610272 T-

b)

( 4 , 2 , 0 )

At ( 4,2,0)

H = 2(H1 + HA)

10 8 H2 = 47(2) / 20°

H = 10 4 14 = 46(4) V2007

\bar{H} = \frac{2\sqrt{5}}{\pi } [1+\frac{1}{4}]a_{Z}

= 1.78\bar{_{Z}} A / m.

c)

( 4 , 8 , 0 )

H = H1 +2H2 + H2

3 = 2- 2

= ਦੋਨ

ਸੰਤ = ਜੀ H3 = --:)

(

= - 0.1178az Am

d)

at ( 0 , 0 , 2 )

H-10 | 47(22) - (a + (2)

=  -10 V64

12- ATV 2ar - Say 2464 784 V68

  5lā, +4āy) 177V84

H3 = 10,8 = -0) *(-4, y) V20

=   (ar + 2az) TV21

! = 1 +,-, * 42)

H = -0.34577,-0.316, Jay +0.1798az A/m

  

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