What is the value of ΔH in kJ for the overall reaction: 4 NO + 6 H2O → 4 NH3 + 5 O2
given these reaction steps?
I. N2 + O2 → 2 NO ΔH = (1.99x10^2) kJ
II. 2 NH3 → N2 + 3 H2 ΔH = (8.910x10^1) kJ
III. 2 H2O → 2 H2 + O2 ΔH = (4.8000x10^2) kJ
Please show work
Question 4 (2 points) What is the value of AH in kJ for the overall reaction: 4 NO + 6 H20 + 4 NH3 +5 O2 given these reaction steps? 1. N2 + O2 + 2 NO AH = (1.97x10^2) kJ II. 2 NH3 + N2 + 3 H2 AH = (8.870x10^1) kJ III. 2 H2O → 2 H2 + O2 AH = (4.7900x10^2) kJ Enter your answer in scientific notation with 3 sig figs. Do not include any units...
Use the ΔH°f values provided to determine ΔH°rxn for the following reaction CH4(g) + 3 Cl2(g) → CHCl3(l) + 3 HCl(g) ΔH°rxn = ? ΔH°f (kJ/mol): -75 -134 -92 A. +662 kJ B. +117 kJ C. -151 kJ D. -335 kJ The equation that corresponds to the enthalpy of formation for NH3(g) is A. N(g) + 3H(g) → NH3(g) B. N(g) + 3/2 H2(g) → NH3(g) C. 1/2 N2(g) + 3H(g) → NH3(g) D. 1/2 N2(g) + 3/2 H2(g) →...
Consider the following data. 2 H2(g) + O2(g) 2 H2O(l) ΔH = -571.7 kJ N2O5(g) + H2O(l) 2 HNO3(l) ΔH = -92.0 kJ N2(g) + 3 O2(g) + H2(g) 2 HNO3O(l) ΔH = -348.2 kJ Use Hess's law to calculate ΔH for the reaction below. 2 N2O5(g) 2 N2(g) + 5 O2(g) ΔH = _____kJ
Consider the following chemical reaction. NH3(g) + 2 O2(g) → HNO3(aq) + H2O(l) Calculate the change in enthalpy (ΔH) for this reaction, using Hess' law and the enthalpy changes for the reactions given below. (1a) 4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(l); ΔH = −1166.0 kJ/mol (2a) 2 NO(g) + O2(g) → 2 NO2(g); ΔH = −116.2 kJ/mol (3a) 3 NO2(g) + H2O(l) → 2 HNO3(aq) + NO(g); ΔH = −137.3 kJ/mol
3. Determine the change in enthalpy for the oxidation of ammonia as follows 4 NH (g)5 O2(g) 3 4 NO(g) + 6 H2O( using the following information: I. N2(g3 H2(g)2 NH3(g) AH-99.22 kJ II. N2(gO2(g) 2 NO(g) AH0 180.5 kJ Ш. )> 2 H20(I) AH= - 571.6 kJ 2 H2(g) Ausaassskl
Calculate the standard reaction enthalpy for the reaction N2H4(ℓ) + H2(g) → 2 NH3(g) given N2H4(ℓ) + O2(g) → N2(g) + 2H2O(g) ∆H ◦ = −543 kJ · mol−1 2 H2(g) + O2(g) → 2 H2O(g) ∆H◦ = −484 kJ · mol−1 N2(g) + 3 H2(g) → 2 NH3(g) ∆H◦ = −92.2 kJ · mol−1 1.) −243 kJ · mol−1 2.) −59 kJ · mol−1 3.) −935 kJ · mol−1 4.) −151 kJ · mol−1 5.) −1119 kJ · mol−1
1) State what is the net reaction. 2) What is the value for ΔH° for the net reaction? (kJ) Consider the following thermochemical equations: (1) CH2OH() + O2(g) HCHO2(/) + H2O(1) AH°= -411 kJ (2) CO(g) + 2H2(g) –CH2OH() AH°=-128 kJ (3) HCHO2(1) CO(g) + H2O(1) AH°= -33 kJ Suppose Equation (1) is reversed and divided by 2; Equations (2) and (3) are multiplied by V2, and then the three adjusted equations are added.
The specific heat of copper is 0.385 J/(g∙°C). If 34.2 g of copper, initially at 25°C, absorbs 4.689 kJ, what will be the final temperature of the copper? a. 25.4°C b. 27.8°C c. 356°C d. 381°C A chemical reaction causes the temperature of 1.0 x 102 g of water in a calorimeter to rise from 25°C to 40°C. The specific heat of water is 4.184 J/(g∙°C). What is the heat of reaction, qP? a. -0.31 kJ b. -0.75 kJ c....
The specific heat of copper is 0.385 J/(g∙°C). If 34.2 g of copper, initially at 25°C, absorbs 4.689 kJ, what will be the final temperature of the copper? a. 25.4°C b. 27.8°C c. 356°C d. 381°C A chemical reaction causes the temperature of 1.0 x 102 g of water in a calorimeter to rise from 25°C to 40°C. The specific heat of water is 4.184 J/(g∙°C). What is the heat of reaction, qP? a. -0.31 kJ b. -0.75 kJ c....
Consider the reaction: H2(g) + (1/2)O2(g) -------> H2O(l) ΔH° = -286 kJ Which of the following is true? (Select all that apply) the reaction is endothermic heat is given off by the surroundings the reaction is exothermic heat is absorbed by the system the enthalpy of the products is less than the that of the reactants