Question

Consider a voltaic cell that uses the reaction

$$ 2 \mathrm{Al}(\mathrm{s})+3 \mathrm{Fe}^{2+}(\mathrm{aq}) \rightarrow 2 \mathrm{Al}^{3+}(\mathrm{aq})+3 \mathrm{Fe}(\mathrm{s}) $$

What is the potential of the cell at \(25^{\circ} \mathrm{C}\). given the following ion concentrations?

$$ \begin{aligned} &{\left[\mathrm{Al}^{3+}\right]=0.10 \mathrm{M}} \\ &{\left[\mathrm{Fe}^{2+}\right]=0.020 \mathrm{M}} \end{aligned} $$

•  1.20 V

•  1.17 V

•  1.03 V

•  1.19 V

Answer 1

here just Nernst equation is used to calculate the cell potential at the given conditions.