Question

Find I1, V2, V3, V4, V5, and V6 using KVL, KCL, and whenever possible voltage division.

750 ? 200 ? 100 ? -12V 82052 33 ? 330 ? 2.7 k? 30012 3.3 k? Sample answers: V2--12V and V%--3.3 V.

Answer 1

I_1 = o A (As there is no return path for current 'I_1') V_330 = 12 KVL in path (1) Rightarrow + V_2 notequalto V_330 + V_33 = 0 V_33 = 0 (because I_33 = 0) No closed path } V_2 = -V_330 = -12 V using the voltage division ppl, V_3 = 12 times 300/300 + 100 + 200 V_3 = 6 V write KVL in path (2), V_4 + V_3 - 5 = 0 Rightarrow V_4 = 5 - V_3 = 5 - 6 V_4 = -1 V write KVL in path (3), + V_5 - V_200 + V_750 = 0 V_750 = 0 as I_750 = 0 } Therefore V_5 = V_200 = 12 times 200/200 + 100 + 300 Therefore V_5 = V_200 = 4V using voltage division ppl, V_2.7 k = 6 times 2.7 k/2.7 k + 3.3 k = 2.7 V write KVL in path (4), - V_6 - V_3 + V_820 + V_2.7 k = 0 V_820 = 0 as I_1 = 0 } Therefore V_6 = V_2.7k - V_3 = 2.7 - 6 V_6 = -3.3 V