Question

Java

/**
* Reports whether or not s1 and s2 contain exactly the same tokens in the same order.
*
* Examples: <br>
* sameTokens("this is a test", " this is a test ") is true <br>
* sameTokens("", "") is true <br>
* sameTokens("hello there", "hello there Joe") is false <br>
* sameTokens("abc def", "def abc") is false <br>
* sameTokens("a", "A") is false
*
* IMPLEMENTATION NOTE: You can write this as an accumulation loop with a twist. Be aware
* of the implications of the short-circuited evaluation of &&.
*/

Answer 1

public class CheckTokens {

public static void main(String[] args) {

String s1 = "abc def";

String s2 = "def abc";

// split array into tokens

String sa1[] = s1.split(" ");

String sa2[] = s2.split(" ");

boolean flag = true;

// check both having same number of tokens

if (sa1.length == sa2.length) {

// iterate and checks for each token

for (int i = 0; i < sa1.length; i++) {

if (!sa1[i].equals(sa2[i])) {

flag = false;

break;

}

}

} else {

System.out.println("false");

return;

}

// prints result

System.out.println(flag);

}

}

$2 public 3 pub September/src/ReadLine.java ring[] args) 4. String s1- abc def; String s2 = def abc; // split array into tokens string sa1 [ ] = s1. split( ); string sa2[] = s2.split( ); boolean flag = true; // check both having same number of tokens if (sal.lengthsa2.length) { 6 7 10 // iterate and checks for each tokern for (int i = 0; 1 く sal. length; i++) { if (sa1[i].equals(sa2[i])) { 12 13 14 15 16 17 18 19 20 21 flag false; break; else System.out.println(false); return; // prints result 23 24 25 26 System.out.println(flag); Console X <terminated> CheckTokens [Java Application] C:SoftPegaEclipse-win64-4.5.2.2\PegaEclipse-win64-4.5.2. false$