Question

14) Consider the following compounds. (1) n-hexane, CH3CH CH2CH2CH CHs, molar mass 86.18 g/mole (II) n-pentanal, CH3CH2CH2CH2CHO, molar mass 87.15 g/mole (III) i-hexane, CHsCH2CH2CH(CH3)2, molar mass = 86.18 g/mole (IV) sodium acetate, CH3 CO2Na, molar mass 82.03 g/mole (V) butanoic acid, CH3CH2CH2CO2H, molar mass 88.11 g/mole (VI) butane-diol, HOCH2CH:CH2CH2OH, molar mass = 92.14 g/mole (VIl) 2,2-dimethylbutane, CHaCH2C(CHaa, molar mass 86.18 g/mole (VII) Ethyl methyl ether, CHaCH2OCH2CH2CHa, molar mass 89.16 g/mole (IX) n-pentanol, C a) Arrange them in order of increasing melting point. HsCH2CH2CH2CH20H, molar mass = 89.16 g/mole b) Arrange them in order of increasing boiling point. c) Arrange them in order of increasing water solubility.

Answer 1

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