Question

f (x) = e.13, oo) k. none x-3 Find the real solution(s) for the following equations. Write none if appropriate a. (x +3)2 +

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Answer #1

Answer:
(a).
none

(b). x=4, x=12

Explanation:

(a). (x+3)2+4=0

x2+9+6x+4=0

x2+6x+13=0 -------------------------------------------------- (1)

Comparing this equation with standard equation, ax2+bx+c=0, we have,

a=1

b=6

c=13

For the equation to have real solutions, b2-4ac>0.

We have,

b2=6^2=36

4ac=4*1*13=52

So, b2-4ac=36-52=-16

so, b2-4ac<0.

Hence, the equation does not have a real solution.  

(b). \sqrt{2x+1} =7-x

Squaring on both sides

2x+1=(7-x)2

2x+1=49+x2-14x

x2-14x+49-2x-1=0

x2-16x+48=0

x2-12x-4x+48=0

x(x-12)-4(x-12)=0

(x-12)(x-4)=0

So we have,

(x-12)=0 => x=12

(x-4)=0 =>x=4

So, real solutions are x=4, x=12.

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