(1 point) In an RLC series circuit, the rms potential difference provided by the source is...
(1 point) In an RLC series circuit, the rms potential difference provided by the source is V = 150 V, and the frequency is f 240 Hz. Given that L = 0.1 H, C = 40 uF, and VR = 20 V, find: T a) I (rms); I A b) R; R 12 c) VL (rms); VL: V d) Vc (rms). Vc = V
(1 point) In an RLC series circuit, the rms potential difference provided by the source is V f = 260 Hz. Given that L -0.35 H, C = 454F, and Vr = 75 V.find: 220 V, and the frequency is a) I (rms) I = 0.6452 A b) R R 116.2 12 c) VL (rms); VL 116.48 V d) Vc (rms). 27.35 Vc V
(1 point) In an RLC series circuit, the rms potential difference provided by the source is V = 220 V, and the frequency is f = Hz. Given that L 0.35H, C = 45 pF, and VR = 75 V. find: 260 2 a) I (rms); A b) R; R 22 c) VL (rms); VL V d) Vc (rms). Vc V
(0 points) In an RLC series circuit, the rms potential difference provided by the source is V = 200 V, and the frequency is f 290 Hz. Given that L = 0.25 H, C = 60 uF, and VR = 65 V, find: = 7T a) I (rms); I = A b) R; R= 12 c) VL (rms); Vi V d) Vc (rms). Vc = V
290 Hz. Given that (0 points) In an RLC series circuit, the rms potential difference provided by the source is V = 170 V, and the frequency is f L 0.2 H, C 30 uF, and VR = 20 V, find: a) I (rms); I A b) R; R= 12 c) VL (rms); VL = V d) Vc (rms). Vc = V
(1 point) In an RLC series circuit, the rms potential difference provided by the source is V=220V, and the frequency is f=170πHz. Given that L=0.7H, C=20μF, and VR=10V(rms). Since everything is stated and asked for in rms you never need to do a conversion with the square root of 2. Find: a) I (rms); I= A This will involve some algebra since you are not given R. I suggest you start by calculating the inductive and capacitive reactances. b) R;...
In an RLC series circuit, the source has a peak potential difference of 150V, and a frequency of 65?Hz. Take ?=15Ω, ?=180?F, ?=0.1H. c) the average power delivered by the source; W d) the power factor. (1 point) In an RLC series circuit, the source has a peak potential difference of 150 V, and a frequency of 95 Hz. Take R = 1512, C = 180 uF, L = 0.1 H. Find: a) XL and Xc; XL = 13 12...
(1 point) In an RLC series circuit, the source has a peak potential difference of 120 V, and a frequency of 55 Hz. Take R=1212, C = 170 uF, L = 0.3 H. Find: a) X and Xc; XL XC = 12 = 12 b) the phase angle; degrees c) the average power delivered by the source; W d) the power factor.
(1 point) In an RLC series circuit, the source has a peak potential difference of 150 V, and a frequency of 70 Hz. Take R = 2012, C = 260 pF, L = 0.1 H. Find: a) XL and Xc; XL = 12 Xc = 12 b) the phase angle; degrees c) the average power delivered by the source; W d) the power factor.
An RLC series circuit is constructed with R = 190.0 Ω, C = 6.00 µF, and L = 0.54 H. The circuit is connected to an AC generator with a frequency of 60.0 Hz that delivers a maximum current of 2.30 A to the circuit. (a) What is the impedance of this circuit? ___ Ω (b) What are the maximum potential differences across each of the three circuit elements (R, L, and C)? VR, max =___ V VL, max =___...