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(1 point) In an RLC series circuit, the rms potential difference provided by the source is...

(1 point) In an RLC series circuit, the rms potential difference provided by the source is V=220V, and the frequency is f=170πHz. Given that L=0.7H, C=20μF, and VR=10V(rms). Since everything is stated and asked for in rms you never need to do a conversion with the square root of 2. Find: a) I (rms); I= A This will involve some algebra since you are not given R. I suggest you start by calculating the inductive and capacitive reactances. b) R; R= Ω c) VL (rms); VL= V (Hint: use the reactance version of Ohm's law.) d) VC (rms). VC= V (Again use the reactance version of Ohm's law.) Wow, those voltages seem larger than the supply voltage!

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