Question

11. Convert the concentration of o.10M Fels into the following units. Fust yourself - the same answer will appear for more than one question because the over charge of an ionic compound is neutral. a) (m/v) of Feci b) Eq/L of Fe ) mEq/mL of Fe d) Eq/L of Cl- e) mEq/mL of Ch A mg FeCl/dL. g) What will happen to a red blood cell if it is immersed in a 0.100M solution of Fecha Isotonic solutions have a TOTAL solute concentration of 0.28M. Solutions, Osmosis, and Dalysis Labdabce-page 14

Answer 1

Juven n 0.10 M Fell, meane 0.10 mol Fedez es present in IL (or 1000 ml solution) g Molar mass = mass of 1 mol felk = 162.2 gmoll So, mass of 0.10 mol fell, = 162.240.10 = 16:22 g - mass of Fellz x 100 - 16-22 x 100 = 1.622 Tor volume of solution 1000 11.68% J Answer b) Eq/L = noi of gm equivalent of Fest volume of solution in L giren mass no. of gm eg. = given mass/16022) torga are of F e 3t quiralent mass = molar mass e eleckon los molar mass of Fellz = 5508 + 3x355 you s 1.62.2 groll So, 162.2 g fell, has re - 55.89 16.22 g felly has Fe = 55.8 x 18 22 = 5. 56 g eq, mas of fest 55.8 16812 - E 1816 So, ned. 1 3 le lost by iron eq/ of test -5.58/18 6 eq=0.3 gear IL ho lai gan

-3 m LX103 a eq/L of ce- - no. of gm equivalent of ce - mealm of fest - mEq of fe 3t . mL of solution volume mEq = 103 Eq, m2 = 103 L So, mea offest = 0.3994 10 10.3 mkg/mL. mL m LX10 d) Similarly - volume of solution in Fellza 162,2 g. 3435.59 ce is present in Feltz = 162.29 16.22 g Fell has ce = 343515 x 1629 16.9 no. of gm eg of Ce = 10,65 - 10.65 i one e gained so, eq/L of ce = 10.65 1.00L e) Similarly mEq of co = 110.65mer - 10.659 by ce 110.65 g ML