3)
for red :
wavelength = 680 nm
C = velocity of light = 3 x 10^8 m / s
frequency = C / lambda
= 3 x 10^8 / 680 x 10^-9
frequency = 4.41 x 10^14 Hz
Energy = h v
= 6.625 x 10^-34 x 4.41 x 10^14
Energy = 2.92 x 10^-19 J
for orange :
waveength = 600 nm
frequency = 5.00 x 10^14 Hz
energy = 3.31 x 10^-19 J
for green :
frequency = 5.66 x 10^14 Hz
Energy = 3.75 x 10^-19 J
for blue :
frequency = 6.52 x 10^14 Hz
Energy = 4.32 x 10^-19 J
on Helium | peach| 1 omplete the following for the row with the The numbers on...
PRE-LABORATORY QUESTIONS (For full credit show your calculations) 1. List the expected color of light and the corresponding wavelength (nm) associated with each cation (use Table 1) Rubidium, Rb Cesium, Cs 2. Calculate the energy associated with the light emitted by each of the elements above (sue equations 1 and 2) Rubidium, Rb Cesium, Cs 11:17 $3.us-east-1.amazonaws.com Flame Tests&Elecrn Ceniguaion 1 of 7 FLAME TESTS & ELECTRON CONFIGURATION INTRODUCTION AND BACKGROUND The chemistry of an element strongly depends on the...