Question

1.) Linear Systems of Equations (estimated time 10min) Consider the following linear system: • + + + m 0 + 0 + + 2 + + + = 7.80USD = 1.35USD + + + + + = 9.65USD Estimate the price of an apple, the price of a watermelon, and the price of a coconut using linear systems in Matlab. (a) Create a matrix A and the vector b that describes this linear system of equations. However, to save memory, please only use single precision numbers (datatype single), i.e. no variables OR computations in double precision (datatype double) are allowed. (b) Solve the linear system in Matlab. Feedback from the grader

Please show how to do single precision. thanks

Answer 1

The code for solving the linear system is :

A = single([2 2 1; 3 1 2; 1 2 3]); % single-precision matrix created B = single([7.80; 7.35; 9.65]); % single-precision vector created X = linsolve(A, B); % linear equation solved and stored in single-precision vector X x = X(1); % value of x assigned y = X(2); % value of y assigned z = X(3); % value of z assigned

The values of x, y and z as found from the code are as follows :

MATLAB R2019b - academic use - 0 x Sign In dos 5 Search Documentation Run and Time HOME PLOTS La Find Files New Open Save Compare Print FILE TD C : Users Current Folder Name - Chegg1.m Chegg2.m Chegg3.m Chegg6.m Chegg7.m Chegg8.asv Chegg8.m APPS EDITOR PUBLISH V IEW Insert fx Run Section Go To Comment % % %. Breakpoints Run Run and ETAdvance Advance Q Find Indent Advance NAVIGATE EDIT BREAKPOINTS RUN user Desktop ▸ MATLAB Teach O Editor - C:\Users\user\Desktop\MATLAB\Teach\Chegg8.m Command Window >> Chegg8 x Workspace Name - HEBBE. Value [2,2,1,3,1,2;1,2,3] [7.8000;7.3500;9.... 0.7500 [0.7500;2.5000;1.... 2.5000 1.3000 single 0.7500 single 2.5000 z = single 1.3000 fx >> Details ENG Select a file to view details 01:05 08-05-2020 scrint in 6 col 19 .